Base | Representation |
---|---|
bin | 10000000111100… |
… | …00111000110011 |
3 | 100102102002120111 |
4 | 20003300320303 |
5 | 234103020103 |
6 | 21225522151 |
7 | 3231134635 |
oct | 1003607063 |
9 | 312362514 |
10 | 135204403 |
11 | 6a357084 |
12 | 39343357 |
13 | 2201b609 |
14 | 13d56a55 |
15 | bd0a86d |
hex | 80f0e33 |
135204403 has 2 divisors, whose sum is σ = 135204404. Its totient is φ = 135204402.
The previous prime is 135204397. The next prime is 135204457. The reversal of 135204403 is 304402531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135204403 - 213 = 135196211 is a prime.
It is not a weakly prime, because it can be changed into another prime (135204463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67602201 + 67602202.
It is an arithmetic number, because the mean of its divisors is an integer number (67602202).
Almost surely, 2135204403 is an apocalyptic number.
135204403 is a deficient number, since it is larger than the sum of its proper divisors (1).
135204403 is an equidigital number, since it uses as much as digits as its factorization.
135204403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1440, while the sum is 22.
The square root of 135204403 is about 11627.7428162133. The cubic root of 135204403 is about 513.2515602676.
Adding to 135204403 its reverse (304402531), we get a palindrome (439606934).
The spelling of 135204403 in words is "one hundred thirty-five million, two hundred four thousand, four hundred three".
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