Base | Representation |
---|---|
bin | 11001001011110101… |
… | …00010101101101011 |
3 | 1021220022011020112111 |
4 | 30211322202231223 |
5 | 210142334133134 |
6 | 10113402023151 |
7 | 656030435605 |
oct | 144572425553 |
9 | 37808136474 |
10 | 13521005419 |
11 | 5809289549 |
12 | 27541a7ab7 |
13 | 13762cca2c |
14 | 923a2c175 |
15 | 542068c64 |
hex | 325ea2b6b |
13521005419 has 2 divisors, whose sum is σ = 13521005420. Its totient is φ = 13521005418.
The previous prime is 13521005371. The next prime is 13521005513. The reversal of 13521005419 is 91450012531.
It is a weak prime.
It is an emirp because it is prime and its reverse (91450012531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13521005419 - 215 = 13520972651 is a prime.
It is a super-2 number, since 2×135210054192 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13521005219) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760502709 + 6760502710.
It is an arithmetic number, because the mean of its divisors is an integer number (6760502710).
Almost surely, 213521005419 is an apocalyptic number.
13521005419 is a deficient number, since it is larger than the sum of its proper divisors (1).
13521005419 is an equidigital number, since it uses as much as digits as its factorization.
13521005419 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5400, while the sum is 31.
The spelling of 13521005419 in words is "thirteen billion, five hundred twenty-one million, five thousand, four hundred nineteen".
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