Base | Representation |
---|---|
bin | 11110101111100100100110… |
… | …101110110011101101010001 |
3 | 122201201222222021201010221011 |
4 | 132233210212232303231101 |
5 | 120210242113401000001 |
6 | 1155322504142530521 |
7 | 40323431420443312 |
oct | 3657444656635521 |
9 | 581658867633834 |
10 | 135210515250001 |
11 | 3a09a503a22944 |
12 | 131b8853b96a41 |
13 | 5a5a3b231a229 |
14 | 255631c390609 |
15 | 1097208478d51 |
hex | 7af926bb3b51 |
135210515250001 has 2 divisors, whose sum is σ = 135210515250002. Its totient is φ = 135210515250000.
The previous prime is 135210515249969. The next prime is 135210515250059. The reversal of 135210515250001 is 100052515012531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 111941478457600 + 23269036792401 = 10580240^2 + 4823799^2 .
It is a cyclic number.
It is not a de Polignac number, because 135210515250001 - 25 = 135210515249969 is a prime.
It is not a weakly prime, because it can be changed into another prime (135210515250061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67605257625000 + 67605257625001.
It is an arithmetic number, because the mean of its divisors is an integer number (67605257625001).
Almost surely, 2135210515250001 is an apocalyptic number.
It is an amenable number.
135210515250001 is a deficient number, since it is larger than the sum of its proper divisors (1).
135210515250001 is an equidigital number, since it uses as much as digits as its factorization.
135210515250001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7500, while the sum is 31.
The spelling of 135210515250001 in words is "one hundred thirty-five trillion, two hundred ten billion, five hundred fifteen million, two hundred fifty thousand, one".
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