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135210515250001 is a prime number
BaseRepresentation
bin11110101111100100100110…
…101110110011101101010001
3122201201222222021201010221011
4132233210212232303231101
5120210242113401000001
61155322504142530521
740323431420443312
oct3657444656635521
9581658867633834
10135210515250001
113a09a503a22944
12131b8853b96a41
135a5a3b231a229
14255631c390609
151097208478d51
hex7af926bb3b51

135210515250001 has 2 divisors, whose sum is σ = 135210515250002. Its totient is φ = 135210515250000.

The previous prime is 135210515249969. The next prime is 135210515250059. The reversal of 135210515250001 is 100052515012531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 111941478457600 + 23269036792401 = 10580240^2 + 4823799^2 .

It is a cyclic number.

It is not a de Polignac number, because 135210515250001 - 25 = 135210515249969 is a prime.

It is not a weakly prime, because it can be changed into another prime (135210515250061) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67605257625000 + 67605257625001.

It is an arithmetic number, because the mean of its divisors is an integer number (67605257625001).

Almost surely, 2135210515250001 is an apocalyptic number.

It is an amenable number.

135210515250001 is a deficient number, since it is larger than the sum of its proper divisors (1).

135210515250001 is an equidigital number, since it uses as much as digits as its factorization.

135210515250001 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7500, while the sum is 31.

The spelling of 135210515250001 in words is "one hundred thirty-five trillion, two hundred ten billion, five hundred fifteen million, two hundred fifty thousand, one".