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135211433 = 724758711
BaseRepresentation
bin10000000111100…
…10100110101001
3100102102110012212
420003302212221
5234103231213
621230014505
73231164300
oct1003624651
9312373185
10135211433
116a361395
1239347435
1322021886
1413d59437
15bd0c9a8
hex80f29a9

135211433 has 12 divisors (see below), whose sum is σ = 160636032. Its totient is φ = 113427720.

The previous prime is 135211397. The next prime is 135211463. The reversal of 135211433 is 334112531.

It is not a de Polignac number, because 135211433 - 210 = 135210409 is a prime.

It is a super-2 number, since 2×1352114332 = 36564263227826978, which contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 135211399 and 135211408.

It is not an unprimeable number, because it can be changed into a prime (135211463) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27053 + ... + 31658.

It is an arithmetic number, because the mean of its divisors is an integer number (13386336).

Almost surely, 2135211433 is an apocalyptic number.

It is an amenable number.

135211433 is a deficient number, since it is larger than the sum of its proper divisors (25424599).

135211433 is an equidigital number, since it uses as much as digits as its factorization.

135211433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 58772 (or 58765 counting only the distinct ones).

The product of its digits is 1080, while the sum is 23.

The square root of 135211433 is about 11628.0451065517. The cubic root of 135211433 is about 513.2604556780.

Adding to 135211433 its reverse (334112531), we get a palindrome (469323964).

The spelling of 135211433 in words is "one hundred thirty-five million, two hundred eleven thousand, four hundred thirty-three".

Divisors: 1 7 47 49 329 2303 58711 410977 2759417 2876839 19315919 135211433