Base | Representation |
---|---|
bin | 11001001011111000… |
… | …01001001101010001 |
3 | 1021220022221120102011 |
4 | 30211330021031101 |
5 | 210142441101413 |
6 | 10113415022521 |
7 | 656034134551 |
oct | 144574111521 |
9 | 37808846364 |
10 | 13521425233 |
11 | 58095459a8 |
12 | 275436aa41 |
13 | 1376418b44 |
14 | 923adb161 |
15 | 5420ed33d |
hex | 325f09351 |
13521425233 has 2 divisors, whose sum is σ = 13521425234. Its totient is φ = 13521425232.
The previous prime is 13521425213. The next prime is 13521425251. The reversal of 13521425233 is 33252412531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12709631169 + 811794064 = 112737^2 + 28492^2 .
It is a cyclic number.
It is not a de Polignac number, because 13521425233 - 217 = 13521294161 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13521425195 and 13521425204.
It is not a weakly prime, because it can be changed into another prime (13521425213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6760712616 + 6760712617.
It is an arithmetic number, because the mean of its divisors is an integer number (6760712617).
Almost surely, 213521425233 is an apocalyptic number.
It is an amenable number.
13521425233 is a deficient number, since it is larger than the sum of its proper divisors (1).
13521425233 is an equidigital number, since it uses as much as digits as its factorization.
13521425233 is an evil number, because the sum of its binary digits is even.
The product of its digits is 21600, while the sum is 31.
Adding to 13521425233 its reverse (33252412531), we get a palindrome (46773837764).
The spelling of 13521425233 in words is "thirteen billion, five hundred twenty-one million, four hundred twenty-five thousand, two hundred thirty-three".
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