Base | Representation |
---|---|
bin | 11110101111101111101100… |
… | …011001110011001001011001 |
3 | 122201210010201001112200001022 |
4 | 132233233230121303021121 |
5 | 120210441004410103131 |
6 | 1155332153424332225 |
7 | 40324332443452055 |
oct | 3657575431631131 |
9 | 581703631480038 |
10 | 135222421566041 |
11 | 3a0a4563807357 |
12 | 131bb017474075 |
13 | 5a5b55bc40054 |
14 | 2556b2b782c65 |
15 | 10976a389137b |
hex | 7afbec673259 |
135222421566041 has 2 divisors, whose sum is σ = 135222421566042. Its totient is φ = 135222421566040.
The previous prime is 135222421566031. The next prime is 135222421566077. The reversal of 135222421566041 is 140665124222531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 95409350308441 + 39813071257600 = 9767771^2 + 6309760^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135222421566041 is a prime.
It is a super-2 number, since 2×1352224215660412 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 135222421565983 and 135222421566001.
It is not a weakly prime, because it can be changed into another prime (135222421566031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67611210783020 + 67611210783021.
It is an arithmetic number, because the mean of its divisors is an integer number (67611210783021).
Almost surely, 2135222421566041 is an apocalyptic number.
It is an amenable number.
135222421566041 is a deficient number, since it is larger than the sum of its proper divisors (1).
135222421566041 is an equidigital number, since it uses as much as digits as its factorization.
135222421566041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 44.
Adding to 135222421566041 its reverse (140665124222531), we get a palindrome (275887545788572).
The spelling of 135222421566041 in words is "one hundred thirty-five trillion, two hundred twenty-two billion, four hundred twenty-one million, five hundred sixty-six thousand, forty-one".
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