Base | Representation |
---|---|
bin | 1100010011001001100100… |
… | …0000111101100101111101 |
3 | 1202212210112210000000212121 |
4 | 3010302121000331211331 |
5 | 3233030324244323031 |
6 | 44432234300002541 |
7 | 2564004424143013 |
oct | 304623100754575 |
9 | 52783483000777 |
10 | 13523124214141 |
11 | 4344141087573 |
12 | 1624a56b30451 |
13 | 7712c0836429 |
14 | 34a74642c8b3 |
15 | 186b7a464011 |
hex | c4c9903d97d |
13523124214141 has 4 divisors (see below), whose sum is σ = 13523226525792. Its totient is φ = 13523021902492.
The previous prime is 13523124214109. The next prime is 13523124214157. The reversal of 13523124214141 is 14141242132531.
13523124214141 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13523124214141 - 25 = 13523124214109 is a prime.
It is a super-2 number, since 2×135231242141412 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13523124214097 and 13523124214106.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13523124214241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50957305 + ... + 51221998.
It is an arithmetic number, because the mean of its divisors is an integer number (3380806631448).
Almost surely, 213523124214141 is an apocalyptic number.
It is an amenable number.
13523124214141 is a deficient number, since it is larger than the sum of its proper divisors (102311651).
13523124214141 is a wasteful number, since it uses less digits than its factorization.
13523124214141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 102311650.
The product of its digits is 23040, while the sum is 34.
Adding to 13523124214141 its reverse (14141242132531), we get a palindrome (27664366346672).
The spelling of 13523124214141 in words is "thirteen trillion, five hundred twenty-three billion, one hundred twenty-four million, two hundred fourteen thousand, one hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •