Base | Representation |
---|---|
bin | 11001001100001100… |
… | …11101110111010001 |
3 | 1021220112001001102011 |
4 | 30212012131313101 |
5 | 210144134200111 |
6 | 10113553022521 |
7 | 656066135113 |
oct | 144606356721 |
9 | 37815031364 |
10 | 13524131281 |
11 | 5810024001 |
12 | 2755254a41 |
13 | 1376b5575b |
14 | 9242033b3 |
15 | 542485021 |
hex | 32619ddd1 |
13524131281 has 2 divisors, whose sum is σ = 13524131282. Its totient is φ = 13524131280.
The previous prime is 13524131273. The next prime is 13524131339. The reversal of 13524131281 is 18213142531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12553185681 + 970945600 = 112041^2 + 31160^2 .
It is a cyclic number.
It is not a de Polignac number, because 13524131281 - 23 = 13524131273 is a prime.
It is a super-2 number, since 2×135241312812 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13524131221) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762065640 + 6762065641.
It is an arithmetic number, because the mean of its divisors is an integer number (6762065641).
Almost surely, 213524131281 is an apocalyptic number.
It is an amenable number.
13524131281 is a deficient number, since it is larger than the sum of its proper divisors (1).
13524131281 is an equidigital number, since it uses as much as digits as its factorization.
13524131281 is an evil number, because the sum of its binary digits is even.
The product of its digits is 5760, while the sum is 31.
The spelling of 13524131281 in words is "thirteen billion, five hundred twenty-four million, one hundred thirty-one thousand, two hundred eighty-one".
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