Base | Representation |
---|---|
bin | 11110110000000011010110… |
… | …010110011010100010111011 |
3 | 122201212011011220001011022001 |
4 | 132300003112112122202323 |
5 | 120211312220230312241 |
6 | 1155350003542441431 |
7 | 40326010442643406 |
oct | 3660032626324273 |
9 | 581764156034261 |
10 | 135243526416571 |
11 | 3a102503963991 |
12 | 13203127433277 |
13 | 5a605434a63a1 |
14 | 2557b706aad3d |
15 | 1097edb600431 |
hex | 7b00d659a8bb |
135243526416571 has 2 divisors, whose sum is σ = 135243526416572. Its totient is φ = 135243526416570.
The previous prime is 135243526416497. The next prime is 135243526416601. The reversal of 135243526416571 is 175614625342531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 135243526416571 - 221 = 135243524319419 is a prime.
It is a super-2 number, since 2×1352435264165712 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135243526416371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67621763208285 + 67621763208286.
It is an arithmetic number, because the mean of its divisors is an integer number (67621763208286).
Almost surely, 2135243526416571 is an apocalyptic number.
135243526416571 is a deficient number, since it is larger than the sum of its proper divisors (1).
135243526416571 is an equidigital number, since it uses as much as digits as its factorization.
135243526416571 is an evil number, because the sum of its binary digits is even.
The product of its digits is 18144000, while the sum is 55.
The spelling of 135243526416571 in words is "one hundred thirty-five trillion, two hundred forty-three billion, five hundred twenty-six million, four hundred sixteen thousand, five hundred seventy-one".
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