Base | Representation |
---|---|
bin | 11001001100010000… |
… | …00010101110111001 |
3 | 1021220112211001011101 |
4 | 30212020002232321 |
5 | 210144240410231 |
6 | 10114005531401 |
7 | 656102505502 |
oct | 144610025671 |
9 | 37815731141 |
10 | 13524544441 |
11 | 5810286461 |
12 | 2755413b61 |
13 | 1376c6b825 |
14 | 9242adba9 |
15 | 542517661 |
hex | 326202bb9 |
13524544441 has 2 divisors, whose sum is σ = 13524544442. Its totient is φ = 13524544440.
The previous prime is 13524544393. The next prime is 13524544447. The reversal of 13524544441 is 14444542531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12945660841 + 578883600 = 113779^2 + 24060^2 .
It is a cyclic number.
It is not a de Polignac number, because 13524544441 - 211 = 13524542393 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13524544441.
It is not a weakly prime, because it can be changed into another prime (13524544447) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762272220 + 6762272221.
It is an arithmetic number, because the mean of its divisors is an integer number (6762272221).
Almost surely, 213524544441 is an apocalyptic number.
It is an amenable number.
13524544441 is a deficient number, since it is larger than the sum of its proper divisors (1).
13524544441 is an equidigital number, since it uses as much as digits as its factorization.
13524544441 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 153600, while the sum is 37.
The spelling of 13524544441 in words is "thirteen billion, five hundred twenty-four million, five hundred forty-four thousand, four hundred forty-one".
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