Base | Representation |
---|---|
bin | 11001001100010011… |
… | …10100101010110001 |
3 | 1021220120200202022211 |
4 | 30212021310222301 |
5 | 210144400323441 |
6 | 10114023532121 |
7 | 656106461206 |
oct | 144611645261 |
9 | 37816622284 |
10 | 13525011121 |
11 | 5810575046 |
12 | 27555ba041 |
13 | 13770a307b |
14 | 924391cad |
15 | 5425aaa81 |
hex | 326274ab1 |
13525011121 has 2 divisors, whose sum is σ = 13525011122. Its totient is φ = 13525011120.
The previous prime is 13525011083. The next prime is 13525011151. The reversal of 13525011121 is 12111052531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8928171121 + 4596840000 = 94489^2 + 67800^2 .
It is an emirp because it is prime and its reverse (12111052531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13525011121 - 233 = 4935076529 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13525011092 and 13525011101.
It is not a weakly prime, because it can be changed into another prime (13525011151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762505560 + 6762505561.
It is an arithmetic number, because the mean of its divisors is an integer number (6762505561).
Almost surely, 213525011121 is an apocalyptic number.
It is an amenable number.
13525011121 is a deficient number, since it is larger than the sum of its proper divisors (1).
13525011121 is an equidigital number, since it uses as much as digits as its factorization.
13525011121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 300, while the sum is 22.
Adding to 13525011121 its reverse (12111052531), we get a palindrome (25636063652).
The spelling of 13525011121 in words is "thirteen billion, five hundred twenty-five million, eleven thousand, one hundred twenty-one".
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