Base | Representation |
---|---|
bin | 1100010011010001000011… |
… | …1001110101000011100001 |
3 | 1202212222201221210112101112 |
4 | 3010310100321311003201 |
5 | 3233043434204010311 |
6 | 44433210031113105 |
7 | 2564105316550064 |
oct | 304642071650341 |
9 | 52788657715345 |
10 | 13525135610081 |
11 | 4344a834a8067 |
12 | 1625318672795 |
13 | 771551470844 |
14 | 34a8976128db |
15 | 186c46d2828b |
hex | c4d10e750e1 |
13525135610081 has 2 divisors, whose sum is σ = 13525135610082. Its totient is φ = 13525135610080.
The previous prime is 13525135610053. The next prime is 13525135610089. The reversal of 13525135610081 is 18001653152531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13520630515681 + 4505094400 = 3677041^2 + 67120^2 .
It is a cyclic number.
It is not a de Polignac number, because 13525135610081 - 210 = 13525135609057 is a prime.
It is a super-2 number, since 2×135251356100812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13525135610089) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762567805040 + 6762567805041.
It is an arithmetic number, because the mean of its divisors is an integer number (6762567805041).
Almost surely, 213525135610081 is an apocalyptic number.
It is an amenable number.
13525135610081 is a deficient number, since it is larger than the sum of its proper divisors (1).
13525135610081 is an equidigital number, since it uses as much as digits as its factorization.
13525135610081 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 41.
The spelling of 13525135610081 in words is "thirteen trillion, five hundred twenty-five billion, one hundred thirty-five million, six hundred ten thousand, eighty-one".
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