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13525135610081 is a prime number
BaseRepresentation
bin1100010011010001000011…
…1001110101000011100001
31202212222201221210112101112
43010310100321311003201
53233043434204010311
644433210031113105
72564105316550064
oct304642071650341
952788657715345
1013525135610081
114344a834a8067
121625318672795
13771551470844
1434a8976128db
15186c46d2828b
hexc4d10e750e1

13525135610081 has 2 divisors, whose sum is σ = 13525135610082. Its totient is φ = 13525135610080.

The previous prime is 13525135610053. The next prime is 13525135610089. The reversal of 13525135610081 is 18001653152531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13520630515681 + 4505094400 = 3677041^2 + 67120^2 .

It is a cyclic number.

It is not a de Polignac number, because 13525135610081 - 210 = 13525135609057 is a prime.

It is a super-2 number, since 2×135251356100812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13525135610089) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762567805040 + 6762567805041.

It is an arithmetic number, because the mean of its divisors is an integer number (6762567805041).

Almost surely, 213525135610081 is an apocalyptic number.

It is an amenable number.

13525135610081 is a deficient number, since it is larger than the sum of its proper divisors (1).

13525135610081 is an equidigital number, since it uses as much as digits as its factorization.

13525135610081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108000, while the sum is 41.

The spelling of 13525135610081 in words is "thirteen trillion, five hundred twenty-five billion, one hundred thirty-five million, six hundred ten thousand, eighty-one".