Base | Representation |
---|---|
bin | 11110110000001101000111… |
… | …100001010001111111101100 |
3 | 122201220011020212012200100210 |
4 | 132300031013201101333230 |
5 | 120212000210321301012 |
6 | 1155354500422022420 |
7 | 40326531402436203 |
oct | 3660150741217754 |
9 | 581804225180323 |
10 | 135254015025132 |
11 | 3a1069a6464823 |
12 | 13205173b77a10 |
13 | 5a6152548a943 |
14 | 255848769c23a |
15 | 109840232623c |
hex | 7b0347851fec |
135254015025132 has 72 divisors (see below), whose sum is σ = 322077976287760. Its totient is φ = 44176487546880.
The previous prime is 135254015025131. The next prime is 135254015025149. The reversal of 135254015025132 is 231520510452531.
It is a super-3 number, since 3×1352540150251323 (a number of 43 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (135254015025131) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23312532 + ... + 28530372.
Almost surely, 2135254015025132 is an apocalyptic number.
135254015025132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
135254015025132 is an abundant number, since it is smaller than the sum of its proper divisors (186823961262628).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
135254015025132 is a wasteful number, since it uses less digits than its factorization.
135254015025132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5218723 (or 5218668 counting only the distinct ones).
The product of its (nonzero) digits is 180000, while the sum is 39.
Adding to 135254015025132 its reverse (231520510452531), we get a palindrome (366774525477663).
The spelling of 135254015025132 in words is "one hundred thirty-five trillion, two hundred fifty-four billion, fifteen million, twenty-five thousand, one hundred thirty-two".
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