Search a number
-
+
13525433143 = 55073245591
BaseRepresentation
bin11001001100010110…
…11011101100110111
31021220121111012020021
430212023123230313
5210200002330033
610114040550011
7656113166455
oct144613335467
937817435207
1013525433143
115810833122
122755782307
1313771c01a1
149244619d5
15542640b2d
hex3262dbb37

13525433143 has 4 divisors (see below), whose sum is σ = 13525733808. Its totient is φ = 13525132480.

The previous prime is 13525433123. The next prime is 13525433147. The reversal of 13525433143 is 34133452531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13525433143 - 29 = 13525432631 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13525433099 and 13525433108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13525433147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 67723 + ... + 177868.

It is an arithmetic number, because the mean of its divisors is an integer number (3381433452).

Almost surely, 213525433143 is an apocalyptic number.

13525433143 is a deficient number, since it is larger than the sum of its proper divisors (300665).

13525433143 is an equidigital number, since it uses as much as digits as its factorization.

13525433143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 300664.

The product of its digits is 64800, while the sum is 34.

Adding to 13525433143 its reverse (34133452531), we get a palindrome (47658885674).

The spelling of 13525433143 in words is "thirteen billion, five hundred twenty-five million, four hundred thirty-three thousand, one hundred forty-three".

Divisors: 1 55073 245591 13525433143