Base | Representation |
---|---|
bin | 11001001100010110… |
… | …11101010100111011 |
3 | 1021220121111112100221 |
4 | 30212023131110323 |
5 | 210200003033203 |
6 | 10114041040511 |
7 | 656113225051 |
oct | 144613352473 |
9 | 37817445327 |
10 | 13525439803 |
11 | 5810838127 |
12 | 2755786137 |
13 | 13771c3225 |
14 | 9244641d1 |
15 | 542642abd |
hex | 3262dd53b |
13525439803 has 2 divisors, whose sum is σ = 13525439804. Its totient is φ = 13525439802.
The previous prime is 13525439797. The next prime is 13525439827. The reversal of 13525439803 is 30893452531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13525439803 - 25 = 13525439771 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13525439803.
It is not a weakly prime, because it can be changed into another prime (13525439843) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6762719901 + 6762719902.
It is an arithmetic number, because the mean of its divisors is an integer number (6762719902).
Almost surely, 213525439803 is an apocalyptic number.
13525439803 is a deficient number, since it is larger than the sum of its proper divisors (1).
13525439803 is an equidigital number, since it uses as much as digits as its factorization.
13525439803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 388800, while the sum is 43.
The spelling of 13525439803 in words is "thirteen billion, five hundred twenty-five million, four hundred thirty-nine thousand, eight hundred three".
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