Base | Representation |
---|---|
bin | 10011101011101010010… |
… | …001010000101111001001 |
3 | 11210022011112200101000011 |
4 | 103223222101100233021 |
5 | 134130010312440424 |
6 | 2513204123111521 |
7 | 166501311236404 |
oct | 23535221205711 |
9 | 4708145611004 |
10 | 1352550124489 |
11 | 481682314543 |
12 | 19a1723725a1 |
13 | 9a711296565 |
14 | 4966c856d3b |
15 | 252b25e7694 |
hex | 13aea450bc9 |
1352550124489 has 2 divisors, whose sum is σ = 1352550124490. Its totient is φ = 1352550124488.
The previous prime is 1352550124447. The next prime is 1352550124517. The reversal of 1352550124489 is 9844210552531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1134367714489 + 218182410000 = 1065067^2 + 467100^2 .
It is a cyclic number.
It is not a de Polignac number, because 1352550124489 - 213 = 1352550116297 is a prime.
It is a super-2 number, since 2×13525501244892 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1352550124789) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676275062244 + 676275062245.
It is an arithmetic number, because the mean of its divisors is an integer number (676275062245).
Almost surely, 21352550124489 is an apocalyptic number.
It is an amenable number.
1352550124489 is a deficient number, since it is larger than the sum of its proper divisors (1).
1352550124489 is an equidigital number, since it uses as much as digits as its factorization.
1352550124489 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728000, while the sum is 49.
The spelling of 1352550124489 in words is "one trillion, three hundred fifty-two billion, five hundred fifty million, one hundred twenty-four thousand, four hundred eighty-nine".
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