Base | Representation |
---|---|
bin | 10011101011101010100… |
… | …111101101110001101001 |
3 | 11210022011221202102020022 |
4 | 103223222213231301221 |
5 | 134130013314314401 |
6 | 2513204453210225 |
7 | 166501412253155 |
oct | 23535247556151 |
9 | 4708157672208 |
10 | 1352556010601 |
11 | 4816856748a4 |
12 | 19a174330975 |
13 | 9a712577773 |
14 | 4966d54a065 |
15 | 252b2dab71b |
hex | 13aea9edc69 |
1352556010601 has 2 divisors, whose sum is σ = 1352556010602. Its totient is φ = 1352556010600.
The previous prime is 1352556010571. The next prime is 1352556010613. The reversal of 1352556010601 is 1060106552531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1339111840000 + 13444170601 = 1157200^2 + 115949^2 .
It is a cyclic number.
It is not a de Polignac number, because 1352556010601 - 234 = 1335376141417 is a prime.
It is a super-3 number, since 3×13525560106013 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1352556010621) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676278005300 + 676278005301.
It is an arithmetic number, because the mean of its divisors is an integer number (676278005301).
Almost surely, 21352556010601 is an apocalyptic number.
It is an amenable number.
1352556010601 is a deficient number, since it is larger than the sum of its proper divisors (1).
1352556010601 is an equidigital number, since it uses as much as digits as its factorization.
1352556010601 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27000, while the sum is 35.
The spelling of 1352556010601 in words is "one trillion, three hundred fifty-two billion, five hundred fifty-six million, ten thousand, six hundred one".
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