Base | Representation |
---|---|
bin | 10011101011110011011… |
… | …101000000000011000011 |
3 | 11210022120021121001111011 |
4 | 103223303131000003003 |
5 | 134130314233244203 |
6 | 2513231305301351 |
7 | 166505161650001 |
oct | 23536335000303 |
9 | 4708507531434 |
10 | 1352704196803 |
11 | 481751288333 |
12 | 19a1b5a94857 |
13 | 9a73718cbcb |
14 | 496850c1a71 |
15 | 252c0dcd76d |
hex | 13af37400c3 |
1352704196803 has 2 divisors, whose sum is σ = 1352704196804. Its totient is φ = 1352704196802.
The previous prime is 1352704196761. The next prime is 1352704196861. The reversal of 1352704196803 is 3086914072531.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1352704196803 is a prime.
It is not a weakly prime, because it can be changed into another prime (1352704196863) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676352098401 + 676352098402.
It is an arithmetic number, because the mean of its divisors is an integer number (676352098402).
It is a 1-persistent number, because it is pandigital, but 2⋅1352704196803 = 2705408393606 is not.
Almost surely, 21352704196803 is an apocalyptic number.
1352704196803 is a deficient number, since it is larger than the sum of its proper divisors (1).
1352704196803 is an equidigital number, since it uses as much as digits as its factorization.
1352704196803 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1088640, while the sum is 49.
The spelling of 1352704196803 in words is "one trillion, three hundred fifty-two billion, seven hundred four million, one hundred ninety-six thousand, eight hundred three".
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