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135305312143 = 1201112660543
BaseRepresentation
bin111111000000011010…
…0110011011110001111
3110221020122211000201011
41332000310303132033
54204101124442033
6142054114230051
712526664114461
oct1760064633617
9427218730634
10135305312143
1152423359721
1222281585327
13c9b40710a1
146797d24131
1537bd9c7ccd
hex1f80d3378f

135305312143 has 4 divisors (see below), whose sum is σ = 135417973888. Its totient is φ = 135192650400.

The previous prime is 135305312117. The next prime is 135305312147. The reversal of 135305312143 is 341213503531.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135305312143 - 225 = 135271757711 is a prime.

It is a super-2 number, since 2×1353053121432 (a number of 23 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135305312147) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56329071 + ... + 56331472.

It is an arithmetic number, because the mean of its divisors is an integer number (33854493472).

Almost surely, 2135305312143 is an apocalyptic number.

135305312143 is a deficient number, since it is larger than the sum of its proper divisors (112661745).

135305312143 is a wasteful number, since it uses less digits than its factorization.

135305312143 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 112661744.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 135305312143 its reverse (341213503531), we get a palindrome (476518815674).

The spelling of 135305312143 in words is "one hundred thirty-five billion, three hundred five million, three hundred twelve thousand, one hundred forty-three".

Divisors: 1 1201 112660543 135305312143