Base | Representation |
---|---|
bin | 111111000000011010… |
… | …0110011011110001111 |
3 | 110221020122211000201011 |
4 | 1332000310303132033 |
5 | 4204101124442033 |
6 | 142054114230051 |
7 | 12526664114461 |
oct | 1760064633617 |
9 | 427218730634 |
10 | 135305312143 |
11 | 52423359721 |
12 | 22281585327 |
13 | c9b40710a1 |
14 | 6797d24131 |
15 | 37bd9c7ccd |
hex | 1f80d3378f |
135305312143 has 4 divisors (see below), whose sum is σ = 135417973888. Its totient is φ = 135192650400.
The previous prime is 135305312117. The next prime is 135305312147. The reversal of 135305312143 is 341213503531.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 135305312143 - 225 = 135271757711 is a prime.
It is a super-2 number, since 2×1353053121432 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135305312147) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 56329071 + ... + 56331472.
It is an arithmetic number, because the mean of its divisors is an integer number (33854493472).
Almost surely, 2135305312143 is an apocalyptic number.
135305312143 is a deficient number, since it is larger than the sum of its proper divisors (112661745).
135305312143 is a wasteful number, since it uses less digits than its factorization.
135305312143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 112661744.
The product of its (nonzero) digits is 16200, while the sum is 31.
Adding to 135305312143 its reverse (341213503531), we get a palindrome (476518815674).
The spelling of 135305312143 in words is "one hundred thirty-five billion, three hundred five million, three hundred twelve thousand, one hundred forty-three".
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