135310041124111 has 16 divisors (see below), whose sum is σ = 155227327061760. Its totient is φ = 115540405485120.

The previous prime is 135310041124057. The next prime is 135310041124121. The reversal of 135310041124111 is 111421140013531.

It is a happy number.

It is not a de Polignac number, because 135310041124111 - 2¹¹ = 135310041122063 is a prime.

It is a super-2 number, since 2×135310041124111² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 135310041124111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135310041124121) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32638941 + ... + 36550246.

It is an arithmetic number, because the mean of its divisors is an integer number (9701707941360).

Almost surely, 2^{135310041124111} is an apocalyptic number.

135310041124111 is a deficient number, since it is larger than the sum of its proper divisors (19917285937649).

135310041124111 is an equidigital number, since it uses as much as digits as its factorization.

135310041124111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69190254.

The product of its (nonzero) digits is 1440, while the sum is 28.

Adding to 135310041124111 its reverse (111421140013531), we get a palindrome (246731181137642).

The spelling of 135310041124111 in words is "one hundred thirty-five trillion, three hundred ten billion, forty-one million, one hundred twenty-four thousand, one hundred eleven".