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13531233540334 = 229323090842219
BaseRepresentation
bin1100010011100111110001…
…0111100101100011101110
31202220120110221010111010011
43010321330113211203232
53233143431241242314
644440055103003434
72564412403240306
oct304717427454356
952816427114104
1013531233540334
114347622636344
12162653a89957a
13771cb3906cb3
1434acb5434606
15186ea23574c4
hexc4e7c5e58ee

13531233540334 has 8 divisors (see below), whose sum is σ = 20366122838040. Its totient is φ = 6742525927656.

The previous prime is 13531233540233. The next prime is 13531233540361. The reversal of 13531233540334 is 43304533213531.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-3 number, since 3×135312335403343 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11545420524 + ... + 11545421695.

It is an arithmetic number, because the mean of its divisors is an integer number (2545765354755).

Almost surely, 213531233540334 is an apocalyptic number.

13531233540334 is a deficient number, since it is larger than the sum of its proper divisors (6834889297706).

13531233540334 is a wasteful number, since it uses less digits than its factorization.

13531233540334 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23090842514.

The product of its (nonzero) digits is 583200, while the sum is 40.

Adding to 13531233540334 its reverse (43304533213531), we get a palindrome (56835766753865).

The spelling of 13531233540334 in words is "thirteen trillion, five hundred thirty-one billion, two hundred thirty-three million, five hundred forty thousand, three hundred thirty-four".

Divisors: 1 2 293 586 23090842219 46181684438 6765616770167 13531233540334