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135312644246077 = 1247910843228163
BaseRepresentation
bin11110110001000011101110…
…000110000000101000111101
3122202002202120211102200202101
4132301003232012000220331
5120213430243411333302
61155441434241425101
740334005315543414
oct3661035606005075
9582082524380671
10135312644246077
113a1298520a1231
12132145b693b191
135a66c09c2a85c
14255b24a08847b
151099bd4557287
hex7b10ee180a3d

135312644246077 has 4 divisors (see below), whose sum is σ = 135323487486720. Its totient is φ = 135301801005436.

The previous prime is 135312644246023. The next prime is 135312644246093. The reversal of 135312644246077 is 770642446213531.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 135312644246077 - 215 = 135312644213309 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135312644246777) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5421601603 + ... + 5421626560.

It is an arithmetic number, because the mean of its divisors is an integer number (33830871871680).

Almost surely, 2135312644246077 is an apocalyptic number.

It is an amenable number.

135312644246077 is a deficient number, since it is larger than the sum of its proper divisors (10843240643).

135312644246077 is a wasteful number, since it uses less digits than its factorization.

135312644246077 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10843240642.

The product of its (nonzero) digits is 20321280, while the sum is 55.

The spelling of 135312644246077 in words is "one hundred thirty-five trillion, three hundred twelve billion, six hundred forty-four million, two hundred forty-six thousand, seventy-seven".

Divisors: 1 12479 10843228163 135312644246077