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135312644246093 is a prime number
BaseRepresentation
bin11110110001000011101110…
…000110000000101001001101
3122202002202120211102200202222
4132301003232012000221031
5120213430243411333333
61155441434241425125
740334005315543436
oct3661035606005115
9582082524380688
10135312644246093
113a1298520a1246
12132145b693b1a5
135a66c09c2a872
14255b24a08848d
151099bd4557298
hex7b10ee180a4d

135312644246093 has 2 divisors, whose sum is σ = 135312644246094. Its totient is φ = 135312644246092.

The previous prime is 135312644246023. The next prime is 135312644246111. The reversal of 135312644246093 is 390642446213531.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108399811179529 + 26912833066564 = 10411523^2 + 5187758^2 .

It is a cyclic number.

It is not a de Polignac number, because 135312644246093 - 210 = 135312644245069 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (135312644246023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67656322123046 + 67656322123047.

It is an arithmetic number, because the mean of its divisors is an integer number (67656322123047).

Almost surely, 2135312644246093 is an apocalyptic number.

It is an amenable number.

135312644246093 is a deficient number, since it is larger than the sum of its proper divisors (1).

135312644246093 is an equidigital number, since it uses as much as digits as its factorization.

135312644246093 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11197440, while the sum is 53.

The spelling of 135312644246093 in words is "one hundred thirty-five trillion, three hundred twelve billion, six hundred forty-four million, two hundred forty-six thousand, ninety-three".