Base | Representation |
---|---|
bin | 11001001101000011… |
… | …11001001100111011 |
3 | 1021221000120100001111 |
4 | 30212201321030323 |
5 | 210203004234042 |
6 | 10114411101151 |
7 | 656214221611 |
oct | 144641711473 |
9 | 37830510044 |
10 | 13531321147 |
11 | 5814094943 |
12 | 27577417b7 |
13 | 13784a2206 |
14 | 9251556b1 |
15 | 542e05517 |
hex | 32687933b |
13531321147 has 2 divisors, whose sum is σ = 13531321148. Its totient is φ = 13531321146.
The previous prime is 13531321127. The next prime is 13531321159. The reversal of 13531321147 is 74112313531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13531321147 - 223 = 13522932539 is a prime.
It is not a weakly prime, because it can be changed into another prime (13531321127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6765660573 + 6765660574.
It is an arithmetic number, because the mean of its divisors is an integer number (6765660574).
Almost surely, 213531321147 is an apocalyptic number.
13531321147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13531321147 is an equidigital number, since it uses as much as digits as its factorization.
13531321147 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7560, while the sum is 31.
Adding to 13531321147 its reverse (74112313531), we get a palindrome (87643634678).
It can be divided in two parts, 1353 and 1321147, that added together give a square (1322500 = 11502).
The spelling of 13531321147 in words is "thirteen billion, five hundred thirty-one million, three hundred twenty-one thousand, one hundred forty-seven".
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