135314050343 has 4 divisors (see below), whose sum is σ = 135317133120. Its totient is φ = 135310967568.

The previous prime is 135314050327. The next prime is 135314050349. The reversal of 135314050343 is 343050413531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 135314050343 - 2⁴ = 135314050327 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (135314050349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1474583 + ... + 1563656.

It is an arithmetic number, because the mean of its divisors is an integer number (33829283280).

Almost surely, 2^135314050343 is an apocalyptic number.

135314050343 is a deficient number, since it is larger than the sum of its proper divisors (3082777).

135314050343 is an equidigital number, since it uses as much as digits as its factorization.

135314050343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3082776.

The product of its (nonzero) digits is 32400, while the sum is 32.

Adding to 135314050343 its reverse (343050413531), we get a palindrome (478364463874).

The spelling of 135314050343 in words is "one hundred thirty-five billion, three hundred fourteen million, fifty thousand, three hundred forty-three".