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135315300002435 = 571719791139191459
BaseRepresentation
bin11110110001000110001100…
…011000111010101010000011
3122202010000102220201002120222
4132301012030120322222003
5120214001213300034220
61155442553551453255
740334131164235340
oct3661061430725203
9582100386632528
10135315300002435
113a12a9952092a3
121321501822722b
135a672411c3017
14255b41ca817c7
151099cdc79ce25
hex7b118c63aa83

135315300002435 has 256 divisors, whose sum is σ = 211679723520000. Its totient is φ = 80819574571008.

The previous prime is 135315300002383. The next prime is 135315300002447. The reversal of 135315300002435 is 534200003513531.

It is a happy number.

It is not a de Polignac number, because 135315300002435 - 26 = 135315300002371 is a prime.

It is a super-2 number, since 2×1353153000024352 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (35).

It is a junction number, because it is equal to n+sod(n) for n = 135315300002395 and 135315300002404.

It is an unprimeable number.

It is a polite number, since it can be written in 255 ways as a sum of consecutive naturals, for example, 92745235736 + ... + 92745237194.

It is an arithmetic number, because the mean of its divisors is an integer number (826873920000).

Almost surely, 2135315300002435 is an apocalyptic number.

135315300002435 is a deficient number, since it is larger than the sum of its proper divisors (76364423517565).

135315300002435 is a wasteful number, since it uses less digits than its factorization.

135315300002435 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2618.

The product of its (nonzero) digits is 81000, while the sum is 35.

Adding to 135315300002435 its reverse (534200003513531), we get a palindrome (669515303515966).

The spelling of 135315300002435 in words is "one hundred thirty-five trillion, three hundred fifteen billion, three hundred million, two thousand, four hundred thirty-five".