Base | Representation |
---|---|
bin | 1100010011101101011100… |
… | …0011100111010111000011 |
3 | 1202220201101222002020121111 |
4 | 3010323113003213113003 |
5 | 3233210040242001431 |
6 | 44440510053504151 |
7 | 2564465166554503 |
oct | 304732703472703 |
9 | 52821358066544 |
10 | 13532755031491 |
11 | 4348233465153 |
12 | 16268a4342057 |
13 | 772196bb2317 |
14 | 34adbb52da03 |
15 | 187040be97b1 |
hex | c4ed70e75c3 |
13532755031491 has 2 divisors, whose sum is σ = 13532755031492. Its totient is φ = 13532755031490.
The previous prime is 13532755031407. The next prime is 13532755031563. The reversal of 13532755031491 is 19413055723531.
It is a strong prime.
It is an emirp because it is prime and its reverse (19413055723531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13532755031491 - 213 = 13532755023299 is a prime.
It is not a weakly prime, because it can be changed into another prime (13532755071491) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6766377515745 + 6766377515746.
It is an arithmetic number, because the mean of its divisors is an integer number (6766377515746).
Almost surely, 213532755031491 is an apocalyptic number.
13532755031491 is a deficient number, since it is larger than the sum of its proper divisors (1).
13532755031491 is an equidigital number, since it uses as much as digits as its factorization.
13532755031491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1701000, while the sum is 49.
The spelling of 13532755031491 in words is "thirteen trillion, five hundred thirty-two billion, seven hundred fifty-five million, thirty-one thousand, four hundred ninety-one".
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