Base | Representation |
---|---|
bin | 10011101100010110111… |
… | …111011111110000000101 |
3 | 11210101002211112110021221 |
4 | 103230112333133300011 |
5 | 134133024403121432 |
6 | 2513410405040341 |
7 | 166526021650351 |
oct | 23542677376005 |
9 | 4711084473257 |
10 | 1353300442117 |
11 | 481a27901258 |
12 | 19a3416b60b1 |
13 | 9a8008727a0 |
14 | 4970036c461 |
15 | 25308408b97 |
hex | 13b16fdfc05 |
1353300442117 has 8 divisors (see below), whose sum is σ = 1457411995256. Its totient is φ = 1249190534592.
The previous prime is 1353300442093. The next prime is 1353300442127. The reversal of 1353300442117 is 7112440033531.
It can be written as a sum of positive squares in 4 ways, for example, as 135601434081 + 1217699008036 = 368241^2 + 1103494^2 .
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 1353300442117 - 27 = 1353300441989 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1353300442127) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1696723 + ... + 2363359.
It is an arithmetic number, because the mean of its divisors is an integer number (182176499407).
Almost surely, 21353300442117 is an apocalyptic number.
It is an amenable number.
1353300442117 is a deficient number, since it is larger than the sum of its proper divisors (104111553139).
1353300442117 is a wasteful number, since it uses less digits than its factorization.
1353300442117 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 822807.
The product of its (nonzero) digits is 30240, while the sum is 34.
Adding to 1353300442117 its reverse (7112440033531), we get a palindrome (8465740475648).
The spelling of 1353300442117 in words is "one trillion, three hundred fifty-three billion, three hundred million, four hundred forty-two thousand, one hundred seventeen".
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