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13533530401 is a prime number
BaseRepresentation
bin11001001101010100…
…10100100100100001
31021221011201120120201
430212222110210201
5210204040433101
610114530305201
7656242052566
oct144652244441
937834646521
1013533530401
115815363776
122758428201
131378a96971
1492556c86d
155431dee01
hex326a94921

13533530401 has 2 divisors, whose sum is σ = 13533530402. Its totient is φ = 13533530400.

The previous prime is 13533530383. The next prime is 13533530411. The reversal of 13533530401 is 10403533531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12516239376 + 1017291025 = 111876^2 + 31895^2 .

It is a cyclic number.

It is not a de Polignac number, because 13533530401 - 215 = 13533497633 is a prime.

It is a super-2 number, since 2×135335304012 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13533530401.

It is not a weakly prime, because it can be changed into another prime (13533530411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6766765200 + 6766765201.

It is an arithmetic number, because the mean of its divisors is an integer number (6766765201).

Almost surely, 213533530401 is an apocalyptic number.

It is an amenable number.

13533530401 is a deficient number, since it is larger than the sum of its proper divisors (1).

13533530401 is an equidigital number, since it uses as much as digits as its factorization.

13533530401 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100, while the sum is 28.

The spelling of 13533530401 in words is "thirteen billion, five hundred thirty-three million, five hundred thirty thousand, four hundred one".