Search a number
-
+
13534001343673 is a prime number
BaseRepresentation
bin1100010011110010000101…
…0101111010110010111001
31202220211121211020110111221
43010330201111322302321
53233220113320444143
644441233454352041
72564541112210636
oct304744125726271
952824554213457
1013534001343673
114348812a22a18
121626b917bb621
13772335170455
1434b098c7718d
151870b53322ed
hexc4f2157acb9

13534001343673 has 2 divisors, whose sum is σ = 13534001343674. Its totient is φ = 13534001343672.

The previous prime is 13534001343647. The next prime is 13534001343701. The reversal of 13534001343673 is 37634310043531.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13397627716729 + 136373626944 = 3660277^2 + 369288^2 .

It is a cyclic number.

It is not a de Polignac number, because 13534001343673 - 25 = 13534001343641 is a prime.

It is not a weakly prime, because it can be changed into another prime (13534001343613) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767000671836 + 6767000671837.

It is an arithmetic number, because the mean of its divisors is an integer number (6767000671837).

Almost surely, 213534001343673 is an apocalyptic number.

It is an amenable number.

13534001343673 is a deficient number, since it is larger than the sum of its proper divisors (1).

13534001343673 is an equidigital number, since it uses as much as digits as its factorization.

13534001343673 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 816480, while the sum is 43.

The spelling of 13534001343673 in words is "thirteen trillion, five hundred thirty-four billion, one million, three hundred forty-three thousand, six hundred seventy-three".