Base | Representation |
---|---|
bin | 1100010011110010000101… |
… | …0101111010110011000001 |
3 | 1202220211121211020110112020 |
4 | 3010330201111322303001 |
5 | 3233220113320444211 |
6 | 44441233454352053 |
7 | 2564541112210650 |
oct | 304744125726301 |
9 | 52824554213466 |
10 | 13534001343681 |
11 | 4348812a22a25 |
12 | 1626b917bb629 |
13 | 772335170460 |
14 | 34b098c77197 |
15 | 1870b5332306 |
hex | c4f2157acc1 |
13534001343681 has 16 divisors (see below), whose sum is σ = 22209643231104. Its totient is φ = 7138813895424.
The previous prime is 13534001343673. The next prime is 13534001343701. The reversal of 13534001343681 is 18634310043531.
It is not a de Polignac number, because 13534001343681 - 23 = 13534001343673 is a prime.
It is a super-2 number, since 2×135340013436812 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13534001343641) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24787547976 + ... + 24787548521.
It is an arithmetic number, because the mean of its divisors is an integer number (1388102701944).
Almost surely, 213534001343681 is an apocalyptic number.
It is an amenable number.
13534001343681 is a deficient number, since it is larger than the sum of its proper divisors (8675641887423).
13534001343681 is a wasteful number, since it uses less digits than its factorization.
13534001343681 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 49575096520.
The product of its (nonzero) digits is 311040, while the sum is 42.
The spelling of 13534001343681 in words is "thirteen trillion, five hundred thirty-four billion, one million, three hundred forty-three thousand, six hundred eighty-one".
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