Base | Representation |
---|---|
bin | 10011101100011110011… |
… | …100111100010000010001 |
3 | 11210101102120001012202121 |
4 | 103230132130330100101 |
5 | 134133303423222203 |
6 | 2513431035414241 |
7 | 166532101540564 |
oct | 23543634742021 |
9 | 4711376035677 |
10 | 1353425601553 |
11 | 481a91517403 |
12 | 19a3775b4381 |
13 | 9a820784c1c |
14 | 49712c2c4db |
15 | 253143cd0bd |
hex | 13b1e73c411 |
1353425601553 has 2 divisors, whose sum is σ = 1353425601554. Its totient is φ = 1353425601552.
The previous prime is 1353425601511. The next prime is 1353425601601. The reversal of 1353425601553 is 3551065243531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1194489427329 + 158936174224 = 1092927^2 + 398668^2 .
It is a cyclic number.
It is not a de Polignac number, because 1353425601553 - 237 = 1215986648081 is a prime.
It is not a weakly prime, because it can be changed into another prime (1353425601503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676712800776 + 676712800777.
It is an arithmetic number, because the mean of its divisors is an integer number (676712800777).
Almost surely, 21353425601553 is an apocalyptic number.
It is an amenable number.
1353425601553 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353425601553 is an equidigital number, since it uses as much as digits as its factorization.
1353425601553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810000, while the sum is 43.
The spelling of 1353425601553 in words is "one trillion, three hundred fifty-three billion, four hundred twenty-five million, six hundred one thousand, five hundred fifty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.065 sec. • engine limits •