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13534551041281 is a prime number
BaseRepresentation
bin1100010011110100001000…
…0110110110010100000001
31202220220001010120222212121
43010331002012312110001
53233222230031310111
644441404212324241
72564560535442604
oct304750206662401
952826033528777
1013534551041281
114348a75243966
121627105913681
137723c20060ca
1434b10bc8833b
151870e8715871
hexc4f421b6501

13534551041281 has 2 divisors, whose sum is σ = 13534551041282. Its totient is φ = 13534551041280.

The previous prime is 13534551041213. The next prime is 13534551041327. The reversal of 13534551041281 is 18214015543531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8383103738881 + 5151447302400 = 2895359^2 + 2269680^2 .

It is a cyclic number.

It is not a de Polignac number, because 13534551041281 - 221 = 13534548944129 is a prime.

It is a super-2 number, since 2×135345510412812 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13534551041681) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767275520640 + 6767275520641.

It is an arithmetic number, because the mean of its divisors is an integer number (6767275520641).

Almost surely, 213534551041281 is an apocalyptic number.

It is an amenable number.

13534551041281 is a deficient number, since it is larger than the sum of its proper divisors (1).

13534551041281 is an equidigital number, since it uses as much as digits as its factorization.

13534551041281 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 288000, while the sum is 43.

The spelling of 13534551041281 in words is "thirteen trillion, five hundred thirty-four billion, five hundred fifty-one million, forty-one thousand, two hundred eighty-one".