Base | Representation |
---|---|
bin | 1100010011110100001000… |
… | …0110110110010100000001 |
3 | 1202220220001010120222212121 |
4 | 3010331002012312110001 |
5 | 3233222230031310111 |
6 | 44441404212324241 |
7 | 2564560535442604 |
oct | 304750206662401 |
9 | 52826033528777 |
10 | 13534551041281 |
11 | 4348a75243966 |
12 | 1627105913681 |
13 | 7723c20060ca |
14 | 34b10bc8833b |
15 | 1870e8715871 |
hex | c4f421b6501 |
13534551041281 has 2 divisors, whose sum is σ = 13534551041282. Its totient is φ = 13534551041280.
The previous prime is 13534551041213. The next prime is 13534551041327. The reversal of 13534551041281 is 18214015543531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8383103738881 + 5151447302400 = 2895359^2 + 2269680^2 .
It is a cyclic number.
It is not a de Polignac number, because 13534551041281 - 221 = 13534548944129 is a prime.
It is a super-2 number, since 2×135345510412812 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13534551041681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767275520640 + 6767275520641.
It is an arithmetic number, because the mean of its divisors is an integer number (6767275520641).
Almost surely, 213534551041281 is an apocalyptic number.
It is an amenable number.
13534551041281 is a deficient number, since it is larger than the sum of its proper divisors (1).
13534551041281 is an equidigital number, since it uses as much as digits as its factorization.
13534551041281 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 288000, while the sum is 43.
The spelling of 13534551041281 in words is "thirteen trillion, five hundred thirty-four billion, five hundred fifty-one million, forty-one thousand, two hundred eighty-one".
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