Base | Representation |
---|---|
bin | 1100010011110101110101… |
… | …0010010001100011001001 |
3 | 1202220221012220121011210212 |
4 | 3010331131102101203021 |
5 | 3233224143244140012 |
6 | 44441521341450505 |
7 | 2564605043266361 |
oct | 304753522214311 |
9 | 52827186534725 |
10 | 13535007021257 |
11 | 4349189674417 |
12 | 1627212570a35 |
13 | 772465617947 |
14 | 34b1526619a1 |
15 | 187123785b22 |
hex | c4f5d4918c9 |
13535007021257 has 2 divisors, whose sum is σ = 13535007021258. Its totient is φ = 13535007021256.
The previous prime is 13535007021241. The next prime is 13535007021301. The reversal of 13535007021257 is 75212070053531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13401010026121 + 133996995136 = 3660739^2 + 366056^2 .
It is a cyclic number.
It is not a de Polignac number, because 13535007021257 - 24 = 13535007021241 is a prime.
It is not a weakly prime, because it can be changed into another prime (13535007221257) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6767503510628 + 6767503510629.
It is an arithmetic number, because the mean of its divisors is an integer number (6767503510629).
Almost surely, 213535007021257 is an apocalyptic number.
It is an amenable number.
13535007021257 is a deficient number, since it is larger than the sum of its proper divisors (1).
13535007021257 is an equidigital number, since it uses as much as digits as its factorization.
13535007021257 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 220500, while the sum is 41.
Adding to 13535007021257 its reverse (75212070053531), we get a palindrome (88747077074788).
The spelling of 13535007021257 in words is "thirteen trillion, five hundred thirty-five billion, seven million, twenty-one thousand, two hundred fifty-seven".
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