Base | Representation |
---|---|
bin | 111111000010000101… |
… | …1100001101111001001 |
3 | 110221101120201202202112 |
4 | 1332010023201233021 |
5 | 4204210032203312 |
6 | 142103444512105 |
7 | 12531246422366 |
oct | 1760413415711 |
9 | 427346652675 |
10 | 135361600457 |
11 | 52452104996 |
12 | 222983ab635 |
13 | c9c291b795 |
14 | 67a15b746d |
15 | 37c38e5d22 |
hex | 1f842e1bc9 |
135361600457 has 2 divisors, whose sum is σ = 135361600458. Its totient is φ = 135361600456.
The previous prime is 135361600453. The next prime is 135361600477. The reversal of 135361600457 is 754006163531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 126454204816 + 8907395641 = 355604^2 + 94379^2 .
It is an emirp because it is prime and its reverse (754006163531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135361600457 - 22 = 135361600453 is a prime.
It is not a weakly prime, because it can be changed into another prime (135361600453) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67680800228 + 67680800229.
It is an arithmetic number, because the mean of its divisors is an integer number (67680800229).
Almost surely, 2135361600457 is an apocalyptic number.
It is an amenable number.
135361600457 is a deficient number, since it is larger than the sum of its proper divisors (1).
135361600457 is an equidigital number, since it uses as much as digits as its factorization.
135361600457 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 226800, while the sum is 41.
Adding to 135361600457 its reverse (754006163531), we get a palindrome (889367763988).
The spelling of 135361600457 in words is "one hundred thirty-five billion, three hundred sixty-one million, six hundred thousand, four hundred fifty-seven".
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