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135363433 is a prime number
BaseRepresentation
bin10000001000101…
…11101101101001
3100102201011201111
420010113231221
5234123112213
621233150321
73232366402
oct1004275551
9312634644
10135363433
116a455607
12393bb3a1
1322075b0a
1413d989a9
15bd3ca3d
hex8117b69

135363433 has 2 divisors, whose sum is σ = 135363434. Its totient is φ = 135363432.

The previous prime is 135363413. The next prime is 135363439. The reversal of 135363433 is 334363531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76947984 + 58415449 = 8772^2 + 7643^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135363433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 135363395 and 135363404.

It is not a weakly prime, because it can be changed into another prime (135363439) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67681716 + 67681717.

It is an arithmetic number, because the mean of its divisors is an integer number (67681717).

Almost surely, 2135363433 is an apocalyptic number.

It is an amenable number.

135363433 is a deficient number, since it is larger than the sum of its proper divisors (1).

135363433 is an equidigital number, since it uses as much as digits as its factorization.

135363433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 29160, while the sum is 31.

The square root of 135363433 is about 11634.5791930778. The cubic root of 135363433 is about 513.4527135160.

The spelling of 135363433 in words is "one hundred thirty-five million, three hundred sixty-three thousand, four hundred thirty-three".