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1353716555657 is a prime number
BaseRepresentation
bin10011101100101111110…
…010110101111110001001
311210102011211112012202112
4103230233302311332021
5134134402414240112
62513515551512105
7166542233603354
oct23545762657611
94712154465675
101353716555657
11482120782544
1219a438b28635
139a868b3650b
144973d72929b
152532ec01a22
hex13b2fcb5f89

1353716555657 has 2 divisors, whose sum is σ = 1353716555658. Its totient is φ = 1353716555656.

The previous prime is 1353716555599. The next prime is 1353716555677. The reversal of 1353716555657 is 7565556173531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1225584057721 + 128132497936 = 1107061^2 + 357956^2 .

It is a cyclic number.

It is not a de Polignac number, because 1353716555657 - 218 = 1353716293513 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1353716555596 and 1353716555605.

It is not a weakly prime, because it can be changed into another prime (1353716555677) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676858277828 + 676858277829.

It is an arithmetic number, because the mean of its divisors is an integer number (676858277829).

Almost surely, 21353716555657 is an apocalyptic number.

It is an amenable number.

1353716555657 is a deficient number, since it is larger than the sum of its proper divisors (1).

1353716555657 is an equidigital number, since it uses as much as digits as its factorization.

1353716555657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 49612500, while the sum is 59.

The spelling of 1353716555657 in words is "one trillion, three hundred fifty-three billion, seven hundred sixteen million, five hundred fifty-five thousand, six hundred fifty-seven".