Base | Representation |
---|---|
bin | 11001001101110000… |
… | …10100101111100011 |
3 | 1021221102122001212101 |
4 | 30212320110233203 |
5 | 210211010413443 |
6 | 10115141111231 |
7 | 656315211445 |
oct | 144670245743 |
9 | 37842561771 |
10 | 13537201123 |
11 | 5817440626 |
12 | 27596b8517 |
13 | 13797806a4 |
14 | 925c46495 |
15 | 5436b784d |
hex | 326e14be3 |
13537201123 has 2 divisors, whose sum is σ = 13537201124. Its totient is φ = 13537201122.
The previous prime is 13537201091. The next prime is 13537201141. The reversal of 13537201123 is 32110273531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13537201123 - 25 = 13537201091 is a prime.
It is a super-2 number, since 2×135372011232 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13537201091 and 13537201100.
It is not a weakly prime, because it can be changed into another prime (13537201163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6768600561 + 6768600562.
It is an arithmetic number, because the mean of its divisors is an integer number (6768600562).
Almost surely, 213537201123 is an apocalyptic number.
13537201123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13537201123 is an equidigital number, since it uses as much as digits as its factorization.
13537201123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3780, while the sum is 28.
Adding to 13537201123 its reverse (32110273531), we get a palindrome (45647474654).
The spelling of 13537201123 in words is "thirteen billion, five hundred thirty-seven million, two hundred one thousand, one hundred twenty-three".
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