Base | Representation |
---|---|
bin | 11001001101110001… |
… | …01111110110010111 |
3 | 1021221102211201011112 |
4 | 30212320233312113 |
5 | 210211022442101 |
6 | 10115143325235 |
7 | 656316153236 |
oct | 144670576627 |
9 | 37842751145 |
10 | 13537312151 |
11 | 5817506a90 |
12 | 275975081b |
13 | 13797bc09c |
14 | 925c74b1d |
15 | 5436da6bb |
hex | 326e2fd97 |
13537312151 has 16 divisors (see below), whose sum is σ = 14843398560. Its totient is φ = 12243934080.
The previous prime is 13537312141. The next prime is 13537312153. The reversal of 13537312151 is 15121373531.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13537312151 is a prime.
It is a super-2 number, since 2×135373121512 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13537312153) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2303645 + ... + 2309513.
It is an arithmetic number, because the mean of its divisors is an integer number (927712410).
Almost surely, 213537312151 is an apocalyptic number.
13537312151 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
13537312151 is a deficient number, since it is larger than the sum of its proper divisors (1306086409).
13537312151 is a wasteful number, since it uses less digits than its factorization.
13537312151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6914.
The product of its digits is 9450, while the sum is 32.
Adding to 13537312151 its reverse (15121373531), we get a palindrome (28658685682).
The spelling of 13537312151 in words is "thirteen billion, five hundred thirty-seven million, three hundred twelve thousand, one hundred fifty-one".
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