Base | Representation |
---|---|
bin | 10011101100110010011… |
… | …101000000001110001011 |
3 | 11210102021221110110022212 |
4 | 103230302131000032023 |
5 | 134140000324141443 |
6 | 2513524223535335 |
7 | 166543315005356 |
oct | 23546235001613 |
9 | 4712257413285 |
10 | 1353761162123 |
11 | 482143979a97 |
12 | 19a44ba5a54b |
13 | 9a875153986 |
14 | 4974561b29d |
15 | 25333ab3618 |
hex | 13b3274038b |
1353761162123 has 2 divisors, whose sum is σ = 1353761162124. Its totient is φ = 1353761162122.
The previous prime is 1353761162041. The next prime is 1353761162189. The reversal of 1353761162123 is 3212611673531.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1353761162123 - 28 = 1353761161867 is a prime.
It is not a weakly prime, because it can be changed into another prime (1353761192123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 676880581061 + 676880581062.
It is an arithmetic number, because the mean of its divisors is an integer number (676880581062).
Almost surely, 21353761162123 is an apocalyptic number.
1353761162123 is a deficient number, since it is larger than the sum of its proper divisors (1).
1353761162123 is an equidigital number, since it uses as much as digits as its factorization.
1353761162123 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 136080, while the sum is 41.
The spelling of 1353761162123 in words is "one trillion, three hundred fifty-three billion, seven hundred sixty-one million, one hundred sixty-two thousand, one hundred twenty-three".
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