Base | Representation |
---|---|
bin | 111111000011010000… |
… | …1111100101101010111 |
3 | 110221111022221010101212 |
4 | 1332012201330231113 |
5 | 4204300131020120 |
6 | 142111414012035 |
7 | 12532235533616 |
oct | 1760641745527 |
9 | 427438833355 |
10 | 135401032535 |
11 | 5247239788a |
12 | 222a964701b |
13 | c9cab46982 |
14 | 67a691d87d |
15 | 37c70d46c5 |
hex | 1f8687cb57 |
135401032535 has 4 divisors (see below), whose sum is σ = 162481239048. Its totient is φ = 108320826024.
The previous prime is 135401032517. The next prime is 135401032537. The reversal of 135401032535 is 535230104531.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 535230104531 = 7121 ⋅75162211.
It is a cyclic number.
It is not a de Polignac number, because 135401032535 - 28 = 135401032279 is a prime.
It is a super-2 number, since 2×1354010325352 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (135401032537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13540103249 + ... + 13540103258.
It is an arithmetic number, because the mean of its divisors is an integer number (40620309762).
Almost surely, 2135401032535 is an apocalyptic number.
135401032535 is a deficient number, since it is larger than the sum of its proper divisors (27080206513).
135401032535 is an equidigital number, since it uses as much as digits as its factorization.
135401032535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27080206512.
The product of its (nonzero) digits is 27000, while the sum is 32.
The spelling of 135401032535 in words is "one hundred thirty-five billion, four hundred one million, thirty-two thousand, five hundred thirty-five".
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