Base | Representation |
---|---|
bin | 11110110010010110011000… |
… | …100101101110000111111011 |
3 | 122202102020200122121222021212 |
4 | 132302112120211232013323 |
5 | 120221404033413001413 |
6 | 1155550313555553335 |
7 | 40343300005351112 |
oct | 3662263045560773 |
9 | 582366618558255 |
10 | 135401404031483 |
11 | 3a16345a739787 |
12 | 132298482bb84b |
13 | 5a723b3b18235 |
14 | 256166a388c79 |
15 | 109c17baa2ca8 |
hex | 7b259896e1fb |
135401404031483 has 2 divisors, whose sum is σ = 135401404031484. Its totient is φ = 135401404031482.
The previous prime is 135401404031371. The next prime is 135401404031653. The reversal of 135401404031483 is 384130404104531.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135401404031483 - 218 = 135401403769339 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 135401404031483.
It is not a weakly prime, because it can be changed into another prime (135401404021483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67700702015741 + 67700702015742.
It is an arithmetic number, because the mean of its divisors is an integer number (67700702015742).
Almost surely, 2135401404031483 is an apocalyptic number.
135401404031483 is a deficient number, since it is larger than the sum of its proper divisors (1).
135401404031483 is an equidigital number, since it uses as much as digits as its factorization.
135401404031483 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 276480, while the sum is 41.
The spelling of 135401404031483 in words is "one hundred thirty-five trillion, four hundred one billion, four hundred four million, thirty-one thousand, four hundred eighty-three".
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