13540402003343 has 4 divisors (see below), whose sum is σ = 13647019342080. Its totient is φ = 13433784664608.

The previous prime is 13540402003259. The next prime is 13540402003357. The reversal of 13540402003343 is 34330020404531.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13540402003343 - 2²⁰ = 13540400954767 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13540402003543) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 53308669178 + ... + 53308669431.

It is an arithmetic number, because the mean of its divisors is an integer number (3411754835520).

Almost surely, 2^{13540402003343} is an apocalyptic number.

13540402003343 is a deficient number, since it is larger than the sum of its proper divisors (106617338737).

13540402003343 is a wasteful number, since it uses less digits than its factorization.

13540402003343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 106617338736.

The product of its (nonzero) digits is 51840, while the sum is 32.

Adding to 13540402003343 its reverse (34330020404531), we get a palindrome (47870422407874).

The spelling of 13540402003343 in words is "thirteen trillion, five hundred forty billion, four hundred two million, three thousand, three hundred forty-three".