Base | Representation |
---|---|
bin | 10011101101000011010… |
… | …011111101010011100001 |
3 | 11210110000122200021211101 |
4 | 103231003103331103201 |
5 | 134141040231103203 |
6 | 2514012250114401 |
7 | 166553321062063 |
oct | 23550323752341 |
9 | 4713018607741 |
10 | 1354044003553 |
11 | 4822795a3a3a |
12 | 19a50a71ba01 |
13 | 9a8bb924777 |
14 | 49771005733 |
15 | 2534d83341d |
hex | 13b434fd4e1 |
1354044003553 has 2 divisors, whose sum is σ = 1354044003554. Its totient is φ = 1354044003552.
The previous prime is 1354044003547. The next prime is 1354044003563. The reversal of 1354044003553 is 3553004404531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1331215211089 + 22828792464 = 1153783^2 + 151092^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1354044003553 is a prime.
It is not a weakly prime, because it can be changed into another prime (1354044003563) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 677022001776 + 677022001777.
It is an arithmetic number, because the mean of its divisors is an integer number (677022001777).
Almost surely, 21354044003553 is an apocalyptic number.
It is an amenable number.
1354044003553 is a deficient number, since it is larger than the sum of its proper divisors (1).
1354044003553 is an equidigital number, since it uses as much as digits as its factorization.
1354044003553 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 37.
The spelling of 1354044003553 in words is "one trillion, three hundred fifty-four billion, forty-four million, three thousand, five hundred fifty-three".
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