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135404434201 is a prime number
BaseRepresentation
bin111111000011010111…
…0111011001100011001
3110221111120022221121111
41332012232323030121
54204302013343301
6142112014540321
712532306462201
oct1760656731431
9427446287544
10135404434201
1152474300583
12222aa8076a1
13c9cb7680aa
1467a7167401
1537c7557551
hex1f86bbb319

135404434201 has 2 divisors, whose sum is σ = 135404434202. Its totient is φ = 135404434200.

The previous prime is 135404434159. The next prime is 135404434213. The reversal of 135404434201 is 102434404531.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 135349674201 + 54760000 = 367899^2 + 7400^2 .

It is a cyclic number.

It is not a de Polignac number, because 135404434201 - 213 = 135404426009 is a prime.

It is not a weakly prime, because it can be changed into another prime (135404434601) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67702217100 + 67702217101.

It is an arithmetic number, because the mean of its divisors is an integer number (67702217101).

Almost surely, 2135404434201 is an apocalyptic number.

It is an amenable number.

135404434201 is a deficient number, since it is larger than the sum of its proper divisors (1).

135404434201 is an equidigital number, since it uses as much as digits as its factorization.

135404434201 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23040, while the sum is 31.

Adding to 135404434201 its reverse (102434404531), we get a palindrome (237838838732).

The spelling of 135404434201 in words is "one hundred thirty-five billion, four hundred four million, four hundred thirty-four thousand, two hundred one".