Base | Representation |
---|---|
bin | 1100010100001010011101… |
… | …1101010111111001100101 |
3 | 1202221110111221221101112220 |
4 | 3011002213131113321211 |
5 | 3233322014340142013 |
6 | 44444235142102553 |
7 | 2565162235321116 |
oct | 305024735277145 |
9 | 52843457841486 |
10 | 13540546412133 |
11 | 43505714a2804 |
12 | 16282b971aa59 |
13 | 772b39140b20 |
14 | 34b51a21020d |
15 | 187349c36b23 |
hex | c50a7757e65 |
13540546412133 has 32 divisors (see below), whose sum is σ = 19587228192000. Its totient is φ = 8270840979456.
The previous prime is 13540546412059. The next prime is 13540546412137. The reversal of 13540546412133 is 33121464504531.
It is not a de Polignac number, because 13540546412133 - 29 = 13540546411621 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13540546412137) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7360816 + ... + 9014582.
It is an arithmetic number, because the mean of its divisors is an integer number (612100881000).
Almost surely, 213540546412133 is an apocalyptic number.
13540546412133 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
It is an amenable number.
13540546412133 is a deficient number, since it is larger than the sum of its proper divisors (6046681779867).
13540546412133 is a wasteful number, since it uses less digits than its factorization.
13540546412133 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1655341.
The product of its (nonzero) digits is 518400, while the sum is 42.
The spelling of 13540546412133 in words is "thirteen trillion, five hundred forty billion, five hundred forty-six million, four hundred twelve thousand, one hundred thirty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •