Base | Representation |
---|---|
bin | 1100010100001100001011… |
… | …0100010111010110101101 |
3 | 1202221111200221122121112002 |
4 | 3011003002310113112231 |
5 | 3233323434342032140 |
6 | 44444352500222045 |
7 | 2565206511003221 |
oct | 305030264272655 |
9 | 52844627577462 |
10 | 13541005424045 |
11 | 43507876041a0 |
12 | 162840739a925 |
13 | 772bb02746c8 |
14 | 34b561176781 |
15 | 1873751a5415 |
hex | c50c2d175ad |
13541005424045 has 8 divisors (see below), whose sum is σ = 17726407100640. Its totient is φ = 9848003944720.
The previous prime is 13541005424039. The next prime is 13541005424047. The reversal of 13541005424045 is 54042450014531.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13541005424045 - 210 = 13541005423021 is a prime.
It is a super-2 number, since 2×135410054240452 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13541005424047) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 123100049255 + ... + 123100049364.
It is an arithmetic number, because the mean of its divisors is an integer number (2215800887580).
Almost surely, 213541005424045 is an apocalyptic number.
It is an amenable number.
13541005424045 is a deficient number, since it is larger than the sum of its proper divisors (4185401676595).
13541005424045 is a wasteful number, since it uses less digits than its factorization.
13541005424045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 246200098635.
The product of its (nonzero) digits is 192000, while the sum is 38.
Adding to 13541005424045 its reverse (54042450014531), we get a palindrome (67583455438576).
The spelling of 13541005424045 in words is "thirteen trillion, five hundred forty-one billion, five million, four hundred twenty-four thousand, forty-five".
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