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135412151050139 is a prime number
BaseRepresentation
bin11110110010100000011001…
…001010010101111110011011
3122202110021102122001002100212
4132302200121022111332123
5120222043041132101024
61155555252225521335
740344130223454035
oct3662403112257633
9582407378032325
10135412151050139
113a167a75097987
121322b9474a324b
135a734074c8182
142561da9804c55
15109c5aa31ea0e
hex7b2819295f9b

135412151050139 has 2 divisors, whose sum is σ = 135412151050140. Its totient is φ = 135412151050138.

The previous prime is 135412151050087. The next prime is 135412151050157. The reversal of 135412151050139 is 931050151214531.

It is a strong prime.

It is an emirp because it is prime and its reverse (931050151214531) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-135412151050139 is a prime.

It is a Sophie Germain prime.

It is a junction number, because it is equal to n+sod(n) for n = 135412151050096 and 135412151050105.

It is not a weakly prime, because it can be changed into another prime (135412151050439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67706075525069 + 67706075525070.

It is an arithmetic number, because the mean of its divisors is an integer number (67706075525070).

Almost surely, 2135412151050139 is an apocalyptic number.

135412151050139 is a deficient number, since it is larger than the sum of its proper divisors (1).

135412151050139 is an equidigital number, since it uses as much as digits as its factorization.

135412151050139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 81000, while the sum is 41.

The spelling of 135412151050139 in words is "one hundred thirty-five trillion, four hundred twelve billion, one hundred fifty-one million, fifty thousand, one hundred thirty-nine".