Base | Representation |
---|---|
bin | 11110110010100000011001… |
… | …001010010101111110011011 |
3 | 122202110021102122001002100212 |
4 | 132302200121022111332123 |
5 | 120222043041132101024 |
6 | 1155555252225521335 |
7 | 40344130223454035 |
oct | 3662403112257633 |
9 | 582407378032325 |
10 | 135412151050139 |
11 | 3a167a75097987 |
12 | 1322b9474a324b |
13 | 5a734074c8182 |
14 | 2561da9804c55 |
15 | 109c5aa31ea0e |
hex | 7b2819295f9b |
135412151050139 has 2 divisors, whose sum is σ = 135412151050140. Its totient is φ = 135412151050138.
The previous prime is 135412151050087. The next prime is 135412151050157. The reversal of 135412151050139 is 931050151214531.
It is a strong prime.
It is an emirp because it is prime and its reverse (931050151214531) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-135412151050139 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 135412151050096 and 135412151050105.
It is not a weakly prime, because it can be changed into another prime (135412151050439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67706075525069 + 67706075525070.
It is an arithmetic number, because the mean of its divisors is an integer number (67706075525070).
Almost surely, 2135412151050139 is an apocalyptic number.
135412151050139 is a deficient number, since it is larger than the sum of its proper divisors (1).
135412151050139 is an equidigital number, since it uses as much as digits as its factorization.
135412151050139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81000, while the sum is 41.
The spelling of 135412151050139 in words is "one hundred thirty-five trillion, four hundred twelve billion, one hundred fifty-one million, fifty thousand, one hundred thirty-nine".
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