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135413051 is a prime number
BaseRepresentation
bin10000001001000…
…11110100111011
3100102210200210012
420010203310323
5234131204201
621234212135
73232664144
oct1004436473
9312720705
10135413051
116a489914
123942404b
1322092587
1413dacacb
15bd4c5bb
hex8123d3b

135413051 has 2 divisors, whose sum is σ = 135413052. Its totient is φ = 135413050.

The previous prime is 135413027. The next prime is 135413071. The reversal of 135413051 is 150314531.

It is a strong prime.

It is an emirp because it is prime and its reverse (150314531) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 135413051 - 26 = 135412987 is a prime.

It is a super-2 number, since 2×1354130512 = 36673388762257202, which contains 22 as substring.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (135413011) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67706525 + 67706526.

It is an arithmetic number, because the mean of its divisors is an integer number (67706526).

Almost surely, 2135413051 is an apocalyptic number.

135413051 is a deficient number, since it is larger than the sum of its proper divisors (1).

135413051 is an equidigital number, since it uses as much as digits as its factorization.

135413051 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 900, while the sum is 23.

The square root of 135413051 is about 11636.7113481430. The cubic root of 135413051 is about 513.5154418910.

Adding to 135413051 its reverse (150314531), we get a palindrome (285727582).

The spelling of 135413051 in words is "one hundred thirty-five million, four hundred thirteen thousand, fifty-one".