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13541355133531 is a prime number
BaseRepresentation
bin1100010100001101011110…
…1010011001101001011011
31202221112121022200200202021
43011003113222121221123
53233330143403233111
644444451311515311
72565221255330341
oct305032752315133
952845538620667
1013541355133531
114350946a500a5
1216284a4528b37
13772c378585b4
1434b5957a9991
15187395c32d71
hexc50d7a99a5b

13541355133531 has 2 divisors, whose sum is σ = 13541355133532. Its totient is φ = 13541355133530.

The previous prime is 13541355133513. The next prime is 13541355133547. The reversal of 13541355133531 is 13533155314531.

Together with previous prime (13541355133513) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13541355133531 - 217 = 13541355002459 is a prime.

It is a super-2 number, since 2×135413551335312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13541355133511) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6770677566765 + 6770677566766.

It is an arithmetic number, because the mean of its divisors is an integer number (6770677566766).

Almost surely, 213541355133531 is an apocalyptic number.

13541355133531 is a deficient number, since it is larger than the sum of its proper divisors (1).

13541355133531 is an equidigital number, since it uses as much as digits as its factorization.

13541355133531 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 607500, while the sum is 43.

The spelling of 13541355133531 in words is "thirteen trillion, five hundred forty-one billion, three hundred fifty-five million, one hundred thirty-three thousand, five hundred thirty-one".